Which of the following alkenes will yield 2-m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Reductive ozonolysis of an alkene involves breaking the $C=C$ double bond and replacing it with two $C=O$ bonds.For $2-$methyl propanal $(CH_3-CH(

Vedclass · Accepted Answer

$2,5-$dimethylhex$-3-$ene

Vedclass · Answer

(C) Reductive ozonolysis of an alkene involves breaking the $C=C$ double bond and replacing it with two $C=O$ bonds.For $2-$methyl propanal $(CH_3-CH(CH_3)-CHO)$,the structure is a $4-$carbon chain with a methyl group on the $2^{nd}$ carbon and an aldehyde group on the $1^{st}$ carbon.If we take $2,5-$dimethylhex$-3-$ene,the structure is $(CH_3)_2CH-CH=CH-CH(CH_3)_2$.Upon reductive ozonolysis,the double bond breaks to form two molecules of $2-$methyl propanal,$(CH_3)_2CH-CHO$.Thus,the correct option is $(C)$.

Which of the following alkenes will yield $2-$methyl propanal on reductive ozonolysis (addition with ozone followed by the reaction with $Zn / H_2 O$)?

Similar Questions

$Ph-CH=C(CH_3)_2 \xleftarrow{HBr} A$ and $Ph-CH=C(CH_3)_2 \xrightarrow[\text{Peroxide}]{HBr} B$. Identify $A$ and $B$.

Explain the hybridization of carbon and the bond structure of ethene $\left( C_2H_4 \right)$ $OR$ Explain: Ethene is a planar molecule.

Identify the major product $X$ in the following reaction:
$1,5,5-\text{trimethylcyclohex-1-ene} \xrightarrow{N.B.S., h\nu} X$

Assertion : Addition of $HBr$ on $2-$butene gives two isomeric products.
Reason : Addition of $HBr$ on $2-$butene follows Markovnikov rule.

The compound $B$ formed in the following sequence of reactions is:
$CH_3-CH_2-CH_2-OH$ $\xrightarrow{PCl_3} A$ $\xrightarrow{Alco. KOH} B$

Vedclass Test Series

Exam Paper Generator

Online Exam Module