Which of the following amines has the lowest | vedclass

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Question

(A) The $pK_{b}$ value is inversely proportional to the basic strength of the amine. $A$ lower $pK_{b}$ value indicates a stronger base.$1$. $C_6H_5NH

Vedclass · Accepted Answer

$C_2H_5NH_2$

Vedclass · Answer

(A) The $pK_{b}$ value is inversely proportional to the basic strength of the amine. $A$ lower $pK_{b}$ value indicates a stronger base.$1$. $C_6H_5NH_2$ (Aniline) is a weak base due to the resonance of the lone pair on nitrogen with the benzene ring.$2$. $(CH_3)_3N$ is a tertiary amine,which is less basic than secondary amines due to steric hindrance.$3$. $C_6H_5CH_2NH_2$ (Benzylamine) is more basic than aniline because the lone pair is not in conjugation with the benzene ring.$4$. $C_2H_5NH_2$ (Ethylamine) is a primary aliphatic amine. In the gas phase,basicity increases with the number of alkyl groups,but in aqueous solution,$C_2H_5NH_2$ is a strong base due to the inductive effect and solvation.Comparing these,$C_2H_5NH_2$ is the strongest base among the given options,hence it has the lowest $pK_{b}$ value.

Which of the following amines has the lowest $pK_{b}$ value?

Similar Questions

Which of the following reactions leads to the formation of benzonitrile?

What is the major product $X$ in the following reaction?
$C_6H_5CONH-C_6H_5 \xrightarrow{Br_2/Fe} X \text{ (major)}$

In the following reaction sequence,$C_2H_5NH_2$ $\xrightarrow{HNO_2} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{NH_3} C$,the compound '$C$' is

$Br-CH_2-(CH_2)_2-CH_2-Br + CH_3NH_2 \to$ The product of the reaction is:

The strongest conjugate acid will result from:

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