Which of the following bond angle orders is c | vedclass

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(D) . In $BCl_3$ ($sp^2$,$120^{\circ}$),$PCl_3$ ($sp^3$,$\approx 107^{\circ}$),and $AsCl_3$ ($sp^3$,$\approx 101^{\circ}$),the bond angle decreases as

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All of the above are correct orders

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(D) . In $BCl_3$ ($sp^2$,$120^{\circ}$),$PCl_3$ ($sp^3$,$\approx 107^{\circ}$),and $AsCl_3$ ($sp^3$,$\approx 101^{\circ}$),the bond angle decreases as the electronegativity of the central atom decreases and the size of the central atom increases. Thus,$BCl_3 > PCl_3 > AsCl_3$ is correct. $B$. Bond angles: $H_2S$ $(\approx 92^{\circ})$,$SF_2$ $(\approx 98^{\circ})$,$NH_3$ $(\approx 107^{\circ})$,and $BF_3$ $(120^{\circ})$. The order $H_2S < SF_2 < NH_3 < BF_3$ is correct. $C$. Bond angles: $OF_2$ $(\approx 103^{\circ})$,$H_2O$ $(\approx 104.5^{\circ})$,and $CH_3-O-CH_3$ $(\approx 111^{\circ})$. The order $OF_2 < H_2O < CH_3-O-CH_3$ is correct. Since all statements are correct,the answer is $D$.

Which of the following bond angle orders is correct?

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