Which of the following bonds is the most pola | vedclass

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(B) The polarity of a bond depends on the difference in electronegativity between the bonded atoms. The greater the electronegativity difference,the m

Vedclass · Accepted Answer

$C - F$

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(B) The polarity of a bond depends on the difference in electronegativity between the bonded atoms. The greater the electronegativity difference,the more polar the bond.Electronegativity values (Pauling scale): $C = 2.55$,$N = 3.04$,$O = 3.44$,$F = 3.98$.Differences:$C - O = |3.44 - 2.55| = 0.89$$C - F = |3.98 - 2.55| = 1.43$$O - F = |3.98 - 3.44| = 0.54$$N - F = |3.98 - 3.04| = 0.94$Since the difference is largest for $C - F$,it is the most polar bond.

Which of the following bonds is the most polar?

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