Which of the following can not be a valid ass | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For an assignment of probabilities to be valid,it must satisfy two conditions: $1$. Each probability $p(\omega_i)$ must satisfy $0 \le p(\omega_i)

Vedclass · Accepted Answer

$-0.1, 0.2, 0.3, 0.4, 0.2, 0.1, -0.1$

Vedclass · Answer

(C) For an assignment of probabilities to be valid,it must satisfy two conditions: $1$. Each probability $p(\omega_i)$ must satisfy $0 \le p(\omega_i) \le 1$. $2$. The sum of all probabilities must be equal to $1$,i.e.,$\sum_{i=1}^{7} p(\omega_i) = 1$. In option $C$,we have negative values $(-0.1)$,which violates the condition $p(\omega_i) \ge 0$. In option $D$,the sum is $0.1 + 0.2 + 0.3 + 0.4 + 0.5 + 0.6 + 0.7 = 2.8$,which is not equal to $1$. Since the question asks which cannot be a valid assignment,both $C$ and $D$ are invalid. However,usually,in such multiple-choice questions,the most fundamental violation is the negative probability. Thus,$C$ is a primary invalid assignment.

$X$	$1$	$2$	$3$	$4$	$5$
$P(X=x)$	$K$	$2K$	$3K$	$2K$	$K$

$X=x$	$1$	$2$	$3$	$4$
$P(X=x)$	$\frac{2}{20}$	$\frac{4}{20}$	$\frac{6}{20}$	$\frac{8}{20}$

$X = x$	$1$	$2$	$3$	$4$	$5$	$6$	$7$	$8$
$P(X = x)$	$0.15$	$0.23$	$k$	$0.10$	$0.20$	$0.08$	$0.07$	$0.05$

Which of the following can not be a valid assignment of probabilities for outcomes of sample space $S = \{\omega_{1}, \omega_{2}, \omega_{3}, \omega_{4}, \omega_{5}, \omega_{6}, \omega_{7}\}$? (Note: The provided table is an example of a valid assignment).

Similar Questions

$A$ random variable $X$ has the probability distribution given below. Its variance is:
$X$ $1$ $2$ $3$ $4$ $5$
$P(X=x)$ $K$ $2K$ $3K$ $2K$ $K$

$A$ fair die is tossed twice in succession. If $X$ denotes the number of sixes in $2$ tosses,then the probability distribution of $X$ is given by

The distribution of a random variable $X$ is given below:
$X=x$ $1$ $2$ $3$ $4$
$P(X=x)$ $\frac{2}{20}$ $\frac{4}{20}$ $\frac{6}{20}$ $\frac{8}{20}$

Then,the standard deviation of $X$ is

$A$ random variable $X$ has the following probability distribution:
$X = x$ $1$ $2$ $3$ $4$ $5$ $6$ $7$ $8$
$P(X = x)$ $0.15$ $0.23$ $k$ $0.10$ $0.20$ $0.08$ $0.07$ $0.05$

For the events $E = \{x : x \text{ is a prime number}\}$ and $F = \{x : x < 4\}$, then $P(E \cup F) = $

$A$ jar contains $7$ white marbles and $3$ blue marbles. Given that $4$ marbles are chosen from the jar at the same time,the standard deviation of the number of blue marbles chosen is $\frac{\sqrt{a}}{b}$,where $a$ and $b$ are co-prime numbers and $a$ is square-free. Then $a + b$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module