(D) salt of strong acid and strong base cannot be hydrolysed. In this case,the ions of the salt do not react with water to produce $H^+$ or $OH^-$ ion

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$D$. $A$ salt of strong acid and strong base

(D) salt of strong acid and strong base cannot be hydrolysed. In this case,the ions of the salt do not react with water to produce $H^+$ or $OH^-$ ions,as they are the conjugate bases/acids of strong acids/bases,which are extremely weak. Therefore,the equilibrium cannot be shifted,and the solution remains neutral.

Class 11 Chemistry 2 Equilibrium: Ionic Equilibrium Salt hydrolysis

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Which of the following cannot be hydrolysed?

A
$A$. $A$ salt of weak acid and strong base
B
$B$. $A$ salt of strong acid and weak base
C
$C$. $A$ salt of weak acid and weak base
D
$D$. $A$ salt of strong acid and strong base

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Class 11

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Chapter

2 Equilibrium: Ionic Equilibrium

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Salt hydrolysis

The $pH$ of an aqueous solution of $CH_3COONa$ of concentration $C \ M$ is given by:

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The $pH$ of a $0.01 \, M$ ammonium cyanide $(NH_4CN)$ solution is $7.02$. If $5 \, L$ of water is added to this solution,the $pH$ will be .......

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If the $pK_b$ for $CN^-$ is $4.7$ at $25\,^oC$,then the $pH$ of a $0.5\,M \,NaCN$ solution is:

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The hydrolysis constant of $0.01 \ M$ methylamine hydrochloride is....... [ Given: $K_b = 5 \times 10^{-4} $ ]

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Match the column $I$ with column $II$ and mark the appropriate choice.

Column $I$ Column $II$

$A$. $CH_3COONa$ $i$. Almost neutral,$pH > 7$ or $< 7$

$B$. $NH_4Cl$ $ii$. Acidic,$pH < 7$

$C$. $NaNO_3$ $iii$. Alkaline,$pH > 7$

$D$. $CH_3COONH_4$ $iv$. Neutral,$pH = 7$

Column $I$	Column $II$
$A$. $CH_3COONa$	$i$. Almost neutral,$pH > 7$ or $< 7$
$B$. $NH_4Cl$	$ii$. Acidic,$pH < 7$
$C$. $NaNO_3$	$iii$. Alkaline,$pH > 7$
$D$. $CH_3COONH_4$	$iv$. Neutral,$pH = 7$

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Which of the following cannot be hydrolysed?

Similar Questions

The $pH$ of an aqueous solution of $CH_3COONa$ of concentration $C \ M$ is given by:

The $pH$ of a $0.01 \, M$ ammonium cyanide $(NH_4CN)$ solution is $7.02$. If $5 \, L$ of water is added to this solution,the $pH$ will be .......

If the $pK_b$ for $CN^-$ is $4.7$ at $25\,^oC$,then the $pH$ of a $0.5\,M \,NaCN$ solution is:

The hydrolysis constant of $0.01 \ M$ methylamine hydrochloride is....... [ Given: $K_b = 5 \times 10^{-4} $ ]

Match the column $I$ with column $II$ and mark the appropriate choice. Column $I$ Column $II$ $A$. $CH_3COONa$ $i$. Almost neutral,$pH > 7$ or $< 7$ $B$. $NH_4Cl$ $ii$. Acidic,$pH < 7$ $C$. $NaNO_3$ $iii$. Alkaline,$pH > 7$ $D$. $CH_3COONH_4$ $iv$. Neutral,$pH = 7$

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Match the column $I$ with column $II$ and mark the appropriate choice.

Column $I$ Column $II$

$A$. $CH_3COONa$ $i$. Almost neutral,$pH > 7$ or $< 7$

$B$. $NH_4Cl$ $ii$. Acidic,$pH < 7$

$C$. $NaNO_3$ $iii$. Alkaline,$pH > 7$

$D$. $CH_3COONH_4$ $iv$. Neutral,$pH = 7$