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(C) . $Zn + 2HCl(dil.) 	o ZnCl_2 + H_2$ (Produces $H_2$)$B$. $NaH + H_2O 	o NaOH + H_2$ (Produces $H_2$)$C$. $4Zn + 10HNO_3(dil.) 	o 4Zn(NO_3)_2 +

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$Zn + HNO_3(dil.) 	o $

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(C) . $Zn + 2HCl(dil.) 	o ZnCl_2 + H_2$ (Produces $H_2$)$B$. $NaH + H_2O 	o NaOH + H_2$ (Produces $H_2$)$C$. $4Zn + 10HNO_3(dil.) 	o 4Zn(NO_3)_2 + N_2O + 5H_2O$ (Produces $N_2O$,not $H_2$)$D$. $2HCOONa \xrightarrow{\Delta } Na_2C_2O_4 + H_2$ (Produces $H_2$)Therefore,$Zn + HNO_3(dil.)$ cannot be used for the preparation of $H_2$ because $HNO_3$ is a strong oxidizing agent and oxidizes $H_2$ to $H_2O$.

Which of the following cannot be used for the preparation of $H_2$?

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