Which of the following carbocations is most s | vedclass

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(B) To determine the stability of carbocations,we look at the number of alkyl groups attached to the positively charged carbon atom (inductive effect

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$(CH_3)_2C^+-CH_2CH_3$

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(B) To determine the stability of carbocations,we look at the number of alkyl groups attached to the positively charged carbon atom (inductive effect and hyperconjugation).$1.$ In option $A$,the carbocation is $(CH_3)_2CH-CH^+-CH_3$. This is a secondary $(2^{\circ})$ carbocation.$2.$ In option $B$,the carbocation is $(CH_3)_2C^+-CH_2CH_3$. This is a tertiary $(3^{\circ})$ carbocation.$3.$ Tertiary carbocations are more stable than secondary carbocations due to greater hyperconjugation and inductive effects from the three alkyl groups attached to the carbocation center.Therefore,$(CH_3)_2C^+-CH_2CH_3$ is more stable.

Which of the following carbocations is most stable?
$A) (CH_3)_2CH-CH^+-CH_3$
$B) (CH_3)_2C^+-CH_2CH_3$

Similar Questions

The most stable carbocation is

The order of decreasing stability of the carbanions is:
$1.$ $(CH_3)_3C^-$
$2.$ $(CH_3)_2CH^-$
$3.$ $CH_3CH_2^-$
$4.$ $C_6H_5CH_2^-$

$CH_3-C(CH_3)_2-CH_2-CH_2^+ \to CH_3-C^+(CH_3)-CH(CH_3)-CH_3$
How many $H^-$ shifts are involved in the above rearrangement?

The shape of a carbonium ion (carbocation) is:

Which of the following is the most stable among the given ions?

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Which of the following carbocations is most stable?$A) (CH_3)_2CH-CH^+-CH_3$$B) (CH_3)_2C^+-CH_2CH_3$