Which of the following cases has the maximum | vedclass

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(B) The size ratio of an anion to its corresponding neutral atom is determined by the increase in electron-electron repulsion upon adding an electron

Vedclass · Accepted Answer

$H^{-}/H$

Vedclass · Answer

(B) The size ratio of an anion to its corresponding neutral atom is determined by the increase in electron-electron repulsion upon adding an electron to the valence shell. For $H$, the addition of an electron to the $1s$ orbital doubles the electron cloud size, resulting in a very high ratio. Comparing the ratios: $1$. For $H^{-}/H$, the radius increases from $37 	ext{ pm}$ to $208 	ext{ pm}$ (ratio $\approx 5.6$). $2$. For $O^{-}/O$, the radius increases from $66 	ext{ pm}$ to $140 	ext{ pm}$ (ratio $\approx 2.1$). $3$. For $F^{-}/F$, the radius increases from $64 	ext{ pm}$ to $133 	ext{ pm}$ (ratio $\approx 2.0$). $4$. For $Na^{-}/Na$, the ratio is significantly smaller as the electron enters a new shell but the nuclear charge is high. Thus, the maximum ratio is observed for $H^{-}/H$.

Which of the following cases has the maximum size ratio of anion to neutral atom?

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