(B) The reduction of an alkyne to a $cis$-alkene is achieved using Lindlar's catalyst,which consists of $Pd$ supported on $CaCO_3$ or $BaSO_4$ and poi

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(B) The reduction of an alkyne to a $cis$-alkene is achieved using Lindlar's catalyst,which consists of $Pd$ supported on $CaCO_3$ or $BaSO_4$ and poisoned with quinoline or lead acetate. This process is known as partial hydrogenation. Therefore,the correct reagent is $Pd-C, \text{ quinoline}$.

Class 11 Chemistry Hydrocarbons Alkyne

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Which of the following catalyst/reagent is used to convert $C \equiv C$ triple bond to $C = C$ double bond to form $cis$ isomer of alkene?

MHT CET 2021 All MHT CET

A
$Na / \text{liquid } NH_3$
B
$Pd-C, \text{ quinoline}$
C
$ZnCl_2 / HCl$
D
$Na / Hg \text{ in } H_2O$

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Hydrocarbons

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Alkyne

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$A$ metallic carbide on treatment with water gives a colourless gas which burns readily in air and which gives a precipitate with ammoniacal silver nitrate solution. The gas evolved is:

Difficult

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Predict the nature of $P$ in the following reaction:
$CH_3-C\equiv C-CH_3 \xrightarrow[heat]{NaNH_2 / \text{inert solvent}} P$

DifficultAIIMS 2014

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Identify the product $D$ in the following series of reaction: $CH_3COOH$ $\xrightarrow{LiAlH_4} A$ $\xrightarrow{H^{+}, 443 \ K} B$ $\xrightarrow{Br_2} C$ $\xrightarrow{alc. KOH} D$

DifficultAIPMT 1998

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When acetylene reacts with $HCl$ in the presence of $HgCl_2$,the product is

Medium

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The structure of the product $(Z)$ in the reactions given below is:
$HC \equiv CH$ $\xrightarrow{NaNH_2, CH_3COCH_3, H^{+}} X$ $\xrightarrow{Hg^{2+}, H_3O^{+}, H_2O} Z$

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Which of the following catalyst/reagent is used to convert $C \equiv C$ triple bond to $C = C$ double bond to form $cis$ isomer of alkene?

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$A$ metallic carbide on treatment with water gives a colourless gas which burns readily in air and which gives a precipitate with ammoniacal silver nitrate solution. The gas evolved is:

Predict the nature of $P$ in the following reaction:$CH_3-C\equiv C-CH_3 \xrightarrow[heat]{NaNH_2 / \text{inert solvent}} P$

Identify the product $D$ in the following series of reaction: $CH_3COOH$ $\xrightarrow{LiAlH_4} A$ $\xrightarrow{H^{+}, 443 \ K} B$ $\xrightarrow{Br_2} C$ $\xrightarrow{alc. KOH} D$

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Predict the nature of $P$ in the following reaction:
$CH_3-C\equiv C-CH_3 \xrightarrow[heat]{NaNH_2 / \text{inert solvent}} P$

The structure of the product $(Z)$ in the reactions given below is:
$HC \equiv CH$ $\xrightarrow{NaNH_2, CH_3COCH_3, H^{+}} X$ $\xrightarrow{Hg^{2+}, H_3O^{+}, H_2O} Z$