Which of the following complex compounds will | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $Ti$ $\rightarrow [Ar] 3d^{2} 4s^{2}, Ti^{3+}$ $\rightarrow [Ar] 3d^{1} 4s^{0}$ ($1$ unpaired electron)$Cr$ $\rightarrow [Ar] 3d^{5} 4s^{1}, Cr^{3

Vedclass · Accepted Answer

$[Cr(NH_3)_6]^{3+}$

Vedclass · Answer

(B) $Ti$ $\rightarrow [Ar] 3d^{2} 4s^{2}, Ti^{3+}$ $\rightarrow [Ar] 3d^{1} 4s^{0}$ ($1$ unpaired electron)$Cr$ $\rightarrow [Ar] 3d^{5} 4s^{1}, Cr^{3+}$ $\rightarrow [Ar] 3d^{3} 4s^{0}$ ($3$ unpaired electrons)$Co$ $\rightarrow [Ar] 3d^{7} 4s^{2}, Co^{3+}$ $\rightarrow [Ar] 3d^{6} 4s^{0}$ ($0$ unpaired electrons because $NH_3$ is a strong field ligand causing pairing)$Zn$ $\rightarrow [Ar] 3d^{10} 4s^{2}, Zn^{2+}$ $\rightarrow [Ar] 3d^{10}$ ($0$ unpaired electrons)Since $[Cr(NH_3)_6]^{3+}$ has the highest number of unpaired electrons $(3)$,it exhibits the highest paramagnetic behaviour.

Which of the following complex compounds will exhibit highest paramagnetic behaviour?
(At. No. $Ti = 22, Cr = 24, Co = 27, Zn = 30$)

Similar Questions

Which of the following ligands can show linkage isomerism?

The number of isomers possible for the complex $K_2[PtClBr_2(SCN)]$ is:

Which of the following is not optically active?

For which pair is the magnetic moment $\mu = \sqrt{15} \ BM$ correct?

Which of the following complexes exhibits the highest paramagnetic behaviour? (Where $gly = \text{glycine}$,$en = \text{ethylenediamine}$ and $bipy = \text{bipyridyl}$) (At. nos. $Ti = 22, V = 23, Cr = 24, Fe = 26, Co = 27$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which of the following complex compounds will exhibit highest paramagnetic behaviour?(At. No. $Ti = 22, Cr = 24, Co = 27, Zn = 30$)