Which of the following complexes will show ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Paramagnetism is directly proportional to the number of unpaired electrons present in the $d$-orbitals. For high-spin complexes,the number of unpa

Vedclass · Accepted Answer

$3d^5$

Vedclass · Answer

(B) Paramagnetism is directly proportional to the number of unpaired electrons present in the $d$-orbitals. For high-spin complexes,the number of unpaired electrons for the given configurations are: $3d^4$: $4$ unpaired electrons $3d^5$: $5$ unpaired electrons $3d^6$: $4$ unpaired electrons $3d^7$: $3$ unpaired electrons Since $3d^5$ has the maximum number of unpaired electrons $(5)$,it will exhibit the maximum paramagnetism.

Which of the following complexes will show maximum paramagnetism?

Similar Questions

The isomer$(s)$ of $[Co(NH_{3})_{4}Cl_{2}]^{+}$ that has/have a $Cl-Co-Cl$ angle of $90^{\circ}$ is/are:

The number of stereoisomers possible for $[Co(ox)_2(Br)(NH_3)]^{2-}$ is $...$. $[ox = \text{oxalate}]$

The complex with a maximum number of stereoisomers is

Which of the following compounds shows optical isomerism?

Which of the following complex ions exhibits geometrical isomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module