Which of the following compounds is planar an | vedclass

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(C) To determine if a molecule is planar and non-polar,we analyze its geometry and dipole moment:$1$. $XeO_3$: It has $sp^3$ hybridization with one lo

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$XeF_4$

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(C) To determine if a molecule is planar and non-polar,we analyze its geometry and dipole moment:$1$. $XeO_3$: It has $sp^3$ hybridization with one lone pair,resulting in a pyramidal geometry. It is polar.$2$. $SF_4$: It has $sp^3d$ hybridization with one lone pair,resulting in a see-saw geometry. It is polar.$3$. $XeF_4$: It has $sp^3d^2$ hybridization with two lone pairs. The lone pairs occupy axial positions to minimize repulsion,resulting in a square planar geometry. The dipole moments of the $Xe-F$ bonds cancel each other out,making it non-polar.$4$. $CF_4$: It has $sp^3$ hybridization with a tetrahedral geometry. While it is non-polar,it is not planar.Therefore,$XeF_4$ is both planar and non-polar.

Which of the following compounds is planar and non-polar?

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