Which of the following compounds decompose on | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Sodium bicarbonate $(NaHCO_3)$ decomposes on heating to form sodium carbonate,water,and carbon dioxide: $2NaHCO_3 \rightarrow Na_2CO_3 + H_2O + CO

Vedclass · Accepted Answer

Both $(A)$ and $(C)$

Vedclass · Answer

(D) Sodium bicarbonate $(NaHCO_3)$ decomposes on heating to form sodium carbonate,water,and carbon dioxide: $2NaHCO_3 \rightarrow Na_2CO_3 + H_2O + CO_2$. Calcium carbonate $(CaCO_3)$ decomposes on heating to form calcium oxide and carbon dioxide: $CaCO_3 \rightarrow CaO + CO_2$. Sodium carbonate $(Na_2CO_3)$ is stable to heat and does not decompose under ordinary heating conditions. Therefore,both $(A)$ and $(C)$ decompose on heating.

List-$I$	List-$II$
$A$. $Na_2CO_3 \cdot 10H_2O$	$I$. $Caustic \ soda$
$B$. $NaOH$	$II$. $Slaked \ lime$
$C$. $Ca(OH)_2$	$III$. $Baking \ soda$
$D$. $NaHCO_3$	$IV$. $Washing \ soda$

Which of the following compounds decompose on heating?

Similar Questions

Which of the following statements is correct?

Which of the following pairs of atomic numbers represents elements belonging to the $s$-block?

Which orders are correct?
$(I)$ Thermal stability: $BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4$
$(II)$ Basic nature: $CaO > MgO > BeO > ZnO$
$(III)$ Solubility in water: $LiOH < NaOH < KOH < RbOH$
$(IV)$ Melting point: $NaCl > KCl > RbCl > CsCl > LiCl$

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A$. $Na_2CO_3 \cdot 10H_2O$ $I$. $Caustic \ soda$
$B$. $NaOH$ $II$. $Slaked \ lime$
$C$. $Ca(OH)_2$ $III$. $Baking \ soda$
$D$. $NaHCO_3$ $IV$. $Washing \ soda$

Give a brief account of the abundance of alkali metals and alkaline earth metals in the Earth's crust.

Vedclass Test Series

Exam Paper Generator

Online Exam Module