Which of the following compounds has the high | vedclass

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(B) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each metal ion:$1$. In $Ni(NO_3)_2$,$Ni$ is in the $+2$ ox

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$MnSO_4$

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(B) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each metal ion:$1$. In $Ni(NO_3)_2$,$Ni$ is in the $+2$ oxidation state $(3d^8)$. It has $n = 2$ unpaired electrons.$2$. In $MnSO_4$,$Mn$ is in the $+2$ oxidation state $(3d^5)$. It has $n = 5$ unpaired electrons.$3$. In $CrCl_3$,$Cr$ is in the $+3$ oxidation state $(3d^3)$. It has $n = 3$ unpaired electrons.$4$. In $FeSO_4$,$Fe$ is in the $+2$ oxidation state $(3d^6)$. It has $n = 4$ unpaired electrons.The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$. Since $Mn^{2+}$ has the highest number of unpaired electrons $(n=5)$,it will have the highest magnetic moment.

Which of the following compounds has the highest magnetic moment?

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