Which of the following compounds is obtained | vedclass

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(C) The reaction of an amide with $Br_2$ and aqueous $KOH$ is known as the $Hofmann$ bromamide degradation reaction.In this reaction, the amide group

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$CH_3CH_2NH_2$

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(C) The reaction of an amide with $Br_2$ and aqueous $KOH$ is known as the $Hofmann$ bromamide degradation reaction.In this reaction, the amide group $(-CONH_2)$ is converted into a primary amine $(-NH_2)$ with the loss of one carbon atom.Propionamide is $CH_3CH_2CONH_2$.Reaction: $CH_3CH_2CONH_2 + Br_2 + 4KOH \rightarrow CH_3CH_2NH_2 + K_2CO_3 + 2KBr + 2H_2O$.The product obtained is ethylamine $(CH_3CH_2NH_2)$.

Which of the following compounds is obtained when propionamide is treated with $Br_2$ and concentrated aqueous $KOH$ solution?

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