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(A) The silver mirror test (Tollens' test) is given by aldehydes and $\alpha$-hydroxy ketones. Among the given compounds:$1$. Formic acid $(HCOOH)$ co

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$A$,$B$ and $C$ only

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(A) The silver mirror test (Tollens' test) is given by aldehydes and $\alpha$-hydroxy ketones. Among the given compounds:$1$. Formic acid $(HCOOH)$ contains an aldehydic hydrogen atom attached to the carbonyl group,which allows it to be oxidized to $CO_2$ and $H_2O$ by Tollens' reagent,thus giving a positive silver mirror test.$2$. Formaldehyde $(HCHO)$ is an aldehyde and gives a positive silver mirror test.$3$. Benzaldehyde $(C_6H_5CHO)$ is an aromatic aldehyde and gives a positive silver mirror test.$4$. Acetone $(CH_3COCH_3)$ is a ketone and does not give a silver mirror test.Therefore,compounds $A$,$B$,and $C$ will give a silver mirror test.

Which of the following compounds will give a silver mirror test with ammoniacal silver nitrate (Tollens' reagent)?
$(A)$ Formic acid
$(B)$ Formaldehyde
$(C)$ Benzaldehyde
$(D)$ Acetone
Choose the correct answer from the options given below:

Similar Questions

What are $X$ and $Y$ respectively in the following reactions?
$C_6H_5COOH \xrightarrow{X} C_6H_5CHO$
$C_6H_5CHO \xrightarrow[OH^-, 293 \ K]{C_6H_5COOH} Y \text{ (Major product)}$

Identify $(A)$ in the following reaction sequence:
$\mathop {(A)}\limits_{\text{gives positive iodoform Test}}$ $\xrightarrow[(ii) H^{+}, H_2O, (iii) \text{conc. } H_2SO_4/\Delta ]{(i) CH_3MgBr} (B)$ $\xrightarrow{O_3/Zn, H_2O}$

$CH_3-CHO + HCN \to A$; Compound $A$ on hydrolysis gives

Complete each synthesis by providing the missing starting material, reagent, or products for the following reactions:

The structure of $(B)$ is

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Which of the following compounds will give a silver mirror test with ammoniacal silver nitrate (Tollens' reagent)?$(A)$ Formic acid$(B)$ Formaldehyde$(C)$ Benzaldehyde$(D)$ AcetoneChoose the correct answer from the options given below: