Which of the following compounds will not und | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Friedel-Crafts reaction requires the formation of a stable carbocation or an acylium ion intermediate. In the case of vinyl chloride $(CH_2=CH-Cl)

Vedclass · Accepted Answer

$CH_2=CH-Cl$ (Vinyl chloride)

Vedclass · Answer

(B) Friedel-Crafts reaction requires the formation of a stable carbocation or an acylium ion intermediate. In the case of vinyl chloride $(CH_2=CH-Cl)$,the chlorine atom is directly attached to an $sp^2$ hybridized carbon atom. The lone pair of electrons on the chlorine atom participates in resonance with the double bond,giving the $C-Cl$ bond partial double bond character. This makes the cleavage of the $C-Cl$ bond very difficult,and the resulting vinyl carbocation $(CH_2=CH^+)$ is highly unstable due to the $sp$ hybridization of the positively charged carbon. Therefore,vinyl chloride does not undergo Friedel-Crafts reaction.

Which of the following compounds will not undergo Friedel-Crafts reaction with benzene?

Similar Questions

Which of the following reactions gives an incorrect major product?

An alkyl bromide $(X)$ reacts with sodium in ether to form $4,5-$diethyl octane. The compound $X$ is:

Which of the following halides shows the highest reactivity towards $S_{N}1$ reaction?

The order of reactivity of the compounds $C_6H_5CH_2Br$,$C_6H_5CH(C_6H_5)Br$,$C_6H_5CH(CH_3)Br$ and $C_6H_5C(CH_3)(C_6H_5)Br$ in $S_N2$ reaction is

The least reactive alkyl chloride in an $S_N2$ reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module