Which of the following conversions represents | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Key Idea: The Fries rearrangement is the rearrangement of a phenolic ester to a hydroxy aryl ketone in the presence of a Lewis acid catalyst.In th

Vedclass · Accepted Answer

$O$-acylated phenol to $C$-acylated phenol

Vedclass · Answer

(A) Key Idea: The Fries rearrangement is the rearrangement of a phenolic ester to a hydroxy aryl ketone in the presence of a Lewis acid catalyst.In this reaction,the acyl group $(RCO-)$ migrates from the oxygen atom of the ester to the ortho or para position of the benzene ring.Thus,it represents the conversion of an $O$-acylated phenol (phenolic ester) to a $C$-acylated phenol (hydroxy aryl ketone).Therefore,option $(A)$ is correct.The reaction is as follows:$C_6H_5OCOR \xrightarrow{AlCl_3} o-HOC_6H_4COR + p-HOC_6H_4COR$

Which of the following conversions represents the Fries rearrangement?

Similar Questions

Identify product $B$ in the following reaction.
Sodium phenoxide $\xrightarrow[6 \text{ atm}]{CO_2, 398 \text{ K}} A$ $\xrightarrow{H_3O^{+}} B$

Which compound does not react with $NaHCO_3$?

In the given reaction sequence,identify the final product $B$:
Phenol $\xrightarrow[(2) CO_2]{(1) OH^-} A$ $\xrightarrow[Pyridine]{CH_3COCl} B$

Explain why the reactivity of the benzene ring increases due to the presence of the $-OH$ group in phenol.

Phenol in the presence of sodium hydroxide reacts with chloroform to form salicylaldehyde. This reaction is known as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module