Which of the following coordination compounds | vedclass

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(B) Optical isomerism is exhibited by coordination compounds that lack a plane of symmetry and a center of symmetry (i.e.,they are chiral).$A$. $trans

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$tris(ethylenediamine)cobalt(III)$ bromide

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(B) Optical isomerism is exhibited by coordination compounds that lack a plane of symmetry and a center of symmetry (i.e.,they are chiral).$A$. $trans-[Cr(en)_2(CN)_2]Cl$ has a plane of symmetry,so it is optically inactive.$B$. $[Co(en)_3]Br_3$ (tris(ethylenediamine)cobalt$(III)$ bromide) contains three bidentate ligands $(en)$. It does not possess a plane of symmetry or a center of symmetry,making it chiral and optically active. It exists as $d$ and $l$ enantiomers.$C$. $[Co(NH_3)_5(NO_2)]I_2$ is a simple octahedral complex with high symmetry,making it optically inactive.$D$. $[Pt(NH_3)_2Cl_2]$ is a square planar complex,which is inherently achiral and optically inactive.Therefore,the correct option is $B$.

List-$I$ (Complex)	List-$II$ (Type of isomerism)
$A$. $[Co(NH_3)_5(NO_2)]Cl_2$	$I$. Solvate isomerism
$B$. $[Co(NH_3)_5(SO_4)]Br$	$II$. Linkage isomerism
$C$. $[Co(NH_3)_6][Cr(CN)_6]$	$III$. Ionization isomerism
$D$. $[Co(H_2O)_6]Cl_3$	$IV$. Coordination isomerism

Which of the following coordination compounds would exhibit optical isomerism?

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