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(C) The industrial production of $H_2SO_4$ (Contact Process) involves the following steps:$1$. $2SO_2 + O_2 \xrightarrow{V_2O_5} 2SO_3$$2$. $SO_3 + H_

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(C) The industrial production of $H_2SO_4$ (Contact Process) involves the following steps:$1$. $2SO_2 + O_2 \xrightarrow{V_2O_5} 2SO_3$$2$. $SO_3 + H_2SO_4 ightarrow H_2S_2O_7$ (Oleum)$3$. $H_2S_2O_7 + H_2O ightarrow 2H_2SO_4$$4$. Concentrated $H_2SO_4$ acts as an oxidizing agent and reacts with metals like $Cu$ to produce $SO_2$: $Cu + 2H_2SO_4 	ext{ (conc.)} ightarrow CuSO_4 + SO_2 + 2H_2O$.Thus,the correct diagram is the one showing the reaction of concentrated $H_2SO_4$ with $Cu$ to form $SO_2$.

Which of the following diagrams is correct for the change of sulphur compounds?

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