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(D) The polarity of a bond is directly proportional to the difference in electronegativity $(\Delta EN)$ between the bonded atoms.Electronegativity va

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(D) The polarity of a bond is directly proportional to the difference in electronegativity $(\Delta EN)$ between the bonded atoms.Electronegativity values are: $F = 4.0$,$O = 3.5$,$Cl = 3.0$,$S = 2.5$,$H = 2.1$.Calculating $\Delta EN$ for each bond:$F-H: 4.0 - 2.1 = 1.9$$O-H: 3.5 - 2.1 = 1.4$$Cl-H: 3.0 - 2.1 = 0.9$$S-H: 2.5 - 2.1 = 0.4$Comparing the polarities: $F-H > O-H > Cl-H > S-H$.Looking at the cycle in the diagrams:$O-H (1.4) \rightarrow Cl-H (0.9)$ (Decrease)$Cl-H (0.9) \rightarrow F-H (1.9)$ (Increase)$F-H (1.9) \rightarrow S-H (0.4)$ (Decrease)$S-H (0.4) \rightarrow O-H (1.4)$ (Increase)This sequence matches Diagram $D$.

Which of the following diagrams shows the correct change in the polarity of the bond?

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