Which of the following displacement (X) - tim | vedclass

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(B) In a displacement $(X)$ versus time $(t)$ graph, the slope represents the velocity of the particle. For a graph to be physically possible, a parti

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(B) In a displacement $(X)$ versus time $(t)$ graph, the slope represents the velocity of the particle. For a graph to be physically possible, a particle must have only one unique position at any given instant of time $(t)$.$1$. In graphs $(A)$ and $(C)$, for every value of time $(t)$, there is a unique value of displacement $(X)$. These are physically possible.$2$. In graph $(B)$, at certain instants of time, the graph shows two different values of displacement $(X)$. This implies the particle is at two places simultaneously, which is impossible.$3$. In graph $(D)$, at certain instants of time, the graph shows multiple values of displacement $(X)$ (vertical segments). This also implies the particle is at multiple places simultaneously, which is impossible.Since both $(B)$ and $(D)$ represent physically impossible scenarios, this question contains multiple correct options.

Which of the following displacement $(X)$ - time $(t)$ graphs is not physically possible?

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