Which of the following electrolytes has the m | vedclass

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(B) According to the $Hardy-Schulze$ rule,the coagulating power of an electrolyte depends on the valency of the active ion (the ion with a charge oppo

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$ZnCl_2$

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(B) According to the $Hardy-Schulze$ rule,the coagulating power of an electrolyte depends on the valency of the active ion (the ion with a charge opposite to that of the colloidal particles).Greater the valency of the flocculating ion,the greater is its coagulating power.In the given options,$ZnCl_2$ dissociates to give $Zn^{2+}$ ions,while $KCl$ and $NaCl$ dissociate to give $K^+$ and $Na^+$ ions respectively.Since the charge on $Zn^{2+}$ $(+2)$ is greater than the charge on $K^+$ $(+1)$ and $Na^+$ $(+1)$,$ZnCl_2$ has the maximum coagulating power.$CCl_4$ is a covalent compound and does not dissociate into ions.

Which of the following electrolytes has the maximum coagulating power?

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