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(A) The actinoids exhibit a wide range of oxidation states due to the comparable energies of $5f$,$6d$,and $7s$ orbitals.$Np$ (Neptunium) and $Pu$ (Pl

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$Np$ and $Pu$

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(A) The actinoids exhibit a wide range of oxidation states due to the comparable energies of $5f$,$6d$,and $7s$ orbitals.$Np$ (Neptunium) and $Pu$ (Plutonium) are known to exhibit oxidation states ranging from $+3$ to $+7$.$U$ (Uranium) typically shows $+3$ to $+6$,while $Am$ (Americium) shows $+3$ to $+6$.Therefore,$Np$ and $Pu$ are the elements that can form compounds in the $+3$ to $+7$ oxidation states.

Which of the following elements can form compounds in $+3$ to $+7$ oxidation states?

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