(A) $N$ forms $p\pi-p\pi$ bond with itself because the $N$ atom has a small atomic size and high electronegativity,allowing it to form $1\sigma$ and $

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) $N$ forms $p\pi-p\pi$ bond with itself because the $N$ atom has a small atomic size and high electronegativity,allowing it to form $1\sigma$ and $2\pi$ bonds (triple bonds) with another $N$ atom. This results in the formation of a stable diatomic molecule,$N_2$.