Which of the following elements has the least | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electronic configurations of the given elements are as follows:$K (Z=19): 1s^2, 2s^2 2p^6, 3s^2 3p^6, 4s^1$. The $M$ shell $(n=3)$ has $2+6 =

Vedclass · Accepted Answer

$K$

Vedclass · Answer

(A) The electronic configurations of the given elements are as follows:$K (Z=19): 1s^2, 2s^2 2p^6, 3s^2 3p^6, 4s^1$. The $M$ shell $(n=3)$ has $2+6 = 8$ electrons.$Mn (Z=25): 1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^5, 4s^2$. The $M$ shell $(n=3)$ has $2+6+5 = 13$ electrons.$Ni (Z=28): 1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^8, 4s^2$. The $M$ shell $(n=3)$ has $2+6+8 = 16$ electrons.$Sc (Z=21): 1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^1, 4s^2$. The $M$ shell $(n=3)$ has $2+6+1 = 9$ electrons.Comparing the number of electrons in the $M$ shell: $K (8) Thus, $K$ has the least number of electrons in its $M$ shell.

Which of the following elements has the least number of electrons in its $M$ shell?

Similar Questions

Compare the energies of the following sets of quantum numbers for a multielectron system:
$A. n=4, \ell=1$
$B. n=4, \ell=2$
$C. n=3, \ell=1$
$D. n=3, \ell=2$
$E. n=4, \ell=0$
Choose the correct order of increasing energy from the options given below:

An electron has a spin quantum number $+1/2$ and magnetic quantum number $-1.$ It cannot be present in :

The total number of orbitals associated with the principal quantum number $n = 5$ is

The set of quantum numbers for the outermost electron for copper $(Cu)$ in its ground state is:

Given:
$(A)\ n = 5, m_l = +1$
$(B)\ n = 2, l = 1, m_l = -1, m_s = -1/2$
The maximum number of electron$(s)$ in an atom that can have the quantum numbers as given in $(A)$ and $(B)$ are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module