Which of the following equimolar solutions is | vedclass

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(C) $1$. Electrical conductivity in a solution depends on the concentration of free ions.$2$. $CH_3COOH$ and $NH_4OH$ are weak electrolytes that disso

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$HCl$

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(C) $1$. Electrical conductivity in a solution depends on the concentration of free ions.$2$. $CH_3COOH$ and $NH_4OH$ are weak electrolytes that dissociate only partially.$3$. $C_6H_{12}O_6$ (glucose) is a non-electrolyte and does not dissociate into ions.$4$. $HCl$ is a strong acid that dissociates completely into $H^+$ and $Cl^-$ ions in water.$5$. Since $HCl$ provides the highest concentration of ions, it is the best conductor of electricity.

Which of the following equimolar solutions is the best conductor of electricity at the same temperature?

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