(D) The stability order of free radicals is $Tertiary > Secondary > Primary > Methyl$. Greater the number of alkyl groups attached to the carbon atom

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(D) The stability order of free radicals is $Tertiary > Secondary > Primary > Methyl$. Greater the number of alkyl groups attached to the carbon atom carrying the odd electron,the greater is the delocalization of the odd electron through hyperconjugation and inductive effects,making the free radical more stable.

Class 11 Chemistry 4 Organic Chemistry: Reaction Mechanism Reactive Intermediates

Easy

Which of the following free radicals is most stable?

A
Primary
B
Methyl
C
Secondary
D
Tertiary

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Class 11 Questions

Class 11

Chemistry Questions

Chapter

4 Organic Chemistry: Reaction Mechanism

Subtopic

Reactive Intermediates

Match the ions given in Column-$I$ with their nature given in Column-$II$.

Column-$I$ Column-$II$

$A$. $CH_3-O^{+}=CH-CH_3$ $1$. Stable due to resonance

$B$. $F_3C^{+}$ $2$. Destabilised due to inductive effect

$C$. $(CH_3)_3C^{-}$ $3$. Stabilised by hyperconjugation

$D$. $CH_3-CH^{+}-CH_3$ $4$. $A$ secondary carbocation

Column-$I$	Column-$II$
$A$. $CH_3-O^{+}=CH-CH_3$	$1$. Stable due to resonance
$B$. $F_3C^{+}$	$2$. Destabilised due to inductive effect
$C$. $(CH_3)_3C^{-}$	$3$. Stabilised by hyperconjugation
$D$. $CH_3-CH^{+}-CH_3$	$4$. $A$ secondary carbocation