Which of the following functions have the max | vedclass

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(D) Let us analyze each function:$1$. For $f(x) = \sin^2 x - \cos^2 x = -\cos 2x$,the range is $[-1, 1]$. The maximum value is $1$.$2$. For $f(x) = \f

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All of the above

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(D) Let us analyze each function:$1$. For $f(x) = \sin^2 x - \cos^2 x = -\cos 2x$,the range is $[-1, 1]$. The maximum value is $1$.$2$. For $f(x) = \frac{\sin 2x - \cos 2x}{\sqrt{2}}$,we can write this as $\sin(2x - \frac{\pi}{4})$. The range is $[-1, 1]$. The maximum value is $1$.$3$. For $f(x) = -\frac{\sin 2x - \cos 2x}{\sqrt{2}}$,we can write this as $-\sin(2x - \frac{\pi}{4}) = \sin(\frac{\pi}{4} - 2x)$. The range is $[-1, 1]$. The maximum value is $1$.Since all functions have a maximum value of $1$,the correct option is $D$.

Which of the following functions have the maximum value unity?

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