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(C) The kinetic energy $(K.E.)$ of an electron in the $n^{th}$ Bohr orbit is given by the formula: $K.E. = \frac{kZe^2}{2r}$.Since the radius of the $

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(C) The kinetic energy $(K.E.)$ of an electron in the $n^{th}$ Bohr orbit is given by the formula: $K.E. = \frac{kZe^2}{2r}$.Since the radius of the $n^{th}$ orbit is $r_n \propto n^2$,we can substitute this into the expression for kinetic energy.Therefore,$K.E. \propto \frac{1}{n^2}$.This relationship indicates that as the principal quantum number $(n)$ increases,the kinetic energy decreases following an inverse square curve. Thus,the correct graph is the one showing $K.E.$ decreasing as $n$ increases.

Which of the following graphs correctly represents the variation of Kinetic Energy $(K.E.)$ of an electron in a Bohr orbit with respect to the principal quantum number $(n)$?

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