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(B) To find the correct matches,we solve each system of linear equations:$1.$ $2x - y = 4$ and $3x - 2y = 5$. From the first,$y = 2x - 4$. Substitutin

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$(1-b), (2-c), (3-d), (4-a)$

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(B) To find the correct matches,we solve each system of linear equations:$1.$ $2x - y = 4$ and $3x - 2y = 5$. From the first,$y = 2x - 4$. Substituting into the second: $3x - 2(2x - 4) = 5 \implies 3x - 4x + 8 = 5 \implies -x = -3 \implies x = 3$. Then $y = 2(3) - 4 = 2$. So,$(1-b)$.$2.$ $5x - y = 14$ and $4x - 3y = 9$. From the first,$y = 5x - 14$. Substituting into the second: $4x - 3(5x - 14) = 9 \implies 4x - 15x + 42 = 9 \implies -11x = -33 \implies x = 3$. Then $y = 5(3) - 14 = 1$. So,$(2-c)$.$3.$ $4x - 3y = 5$ and $3x - y = 5$. From the second,$y = 3x - 5$. Substituting into the first: $4x - 3(3x - 5) = 5 \implies 4x - 9x + 15 = 5 \implies -5x = -10 \implies x = 2$. Then $y = 3(2) - 5 = 1$. So,$(3-d)$.$4.$ $3x - 2y = -1$ and $2x - 5y = -8$. Multiplying the first by $5$ and the second by $2$: $15x - 10y = -5$ and $4x - 10y = -16$. Subtracting: $11x = 11 \implies x = 1$. Then $3(1) - 2y = -1 \implies -2y = -4 \implies y = 2$. So,$(4-a)$.The correct matching is $(1-b), (2-c), (3-d), (4-a)$.

Part $I$	Part $II$
$1.$ The solution of $2x - y = 4$ and $3x - 2y = 5$	$a.$ $x = 3, y = 2$
$2.$ The solution of $5x - y = 14$ and $4x - 3y = 9$	$b.$ $x = 3, y = 1$
$3.$ The solution of $4x - 3y = 5$ and $3x - y = 5$	$c.$ $x = 2, y = 1$
$4.$ The solution of $3x - 2y = -1$ and $2x - 5y = -8$	$d.$ $x = 1, y = 2$

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