Which of the following has been arranged in o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Bond dissociation energy is inversely proportional to bond length: $BDE \propto \frac{1}{	ext{Bond length}}$.As we move from left to right across

Vedclass · Accepted Answer

$Cl-O > S-O > P-O$

Vedclass · Answer

(D) Bond dissociation energy is inversely proportional to bond length: $BDE \propto \frac{1}{	ext{Bond length}}$.As we move from left to right across a period,the atomic size decreases,which leads to a decrease in bond length.The order of atomic size is $P > S > Cl$,therefore the order of bond length is $P-O > S-O > Cl-O$.Since bond dissociation energy is inversely proportional to bond length,the order of $BDE$ is $Cl-O > S-O > P-O$.

Element	Electronegativity Value
$W$	$2.7$
$X$	$2.1$
$Y$	$0.8$
$Z$	$3.4$

Column $I$ (Molecules)	Column $II$ (Number of lone pairs on central atom)
$A. \ NH_3$	$1. \ \text{Two}$
$B. \ H_2O$	$2. \ \text{Three}$
$C. \ XeF_2$	$3. \ \text{Zero}$
$D. \ CH_4$	$4. \ \text{Four}$
	$5. \ \text{One}$

Which of the following has been arranged in order of decreasing bond dissociation energy:

Similar Questions

Which of the following structures is the most preferred and hence of lowest energy for $SO_3$?

Element Electronegativity Value
$W$ $2.7$
$X$ $2.1$
$Y$ $0.8$
$Z$ $3.4$
The incorrect statement regarding the given information is:

The sum of $\pi$-bonds present in peroxodisulphuric acid and pyrosulphuric acid is:

In which of the following molecules do all the atoms lie in one plane?

Vedclass Test Series

Exam Paper Generator

Online Exam Module