Which of the following has unpaired electron( | vedclass

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(B) The molecular orbital configuration for $O_2^-$ (total $17$ electrons) is: $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_x)^2(\pi 2p_y)^2(\pi 2p_z)^2(

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$O_2^-$

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(B) The molecular orbital configuration for $O_2^-$ (total $17$ electrons) is: $KK(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_x)^2(\pi 2p_y)^2(\pi 2p_z)^2(\pi^* 2p_y)^2(\pi^* 2p_z)^1$.Since there is one unpaired electron in the $\pi^* 2p_z$ orbital,$O_2^-$ is paramagnetic.For $N_2$ ($14$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\pi 2p_y)^2(\pi 2p_z)^2(\sigma 2p_x)^2$ (all paired).For $N_2^{2+}$ ($12$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\pi 2p_y)^2(\pi 2p_z)^2$ (all paired).For $O_2^{2-}$ ($18$ electrons): $(\sigma 1s)^2(\sigma^* 1s)^2(\sigma 2s)^2(\sigma^* 2s)^2(\sigma 2p_x)^2(\pi 2p_y)^2(\pi 2p_z)^2(\pi^* 2p_y)^2(\pi^* 2p_z)^2$ (all paired).

Which of the following has unpaired electron$(s)$?

Similar Questions

Given below are two statements:
Statement $(I)$: The correct sequence of bond lengths in the following species is:
$O_2^+ < O_2 < O_2^- < O_2^{2-}$
Statement $(II)$: The correct sequence of number of unpaired electrons in the following species is:
$O_2 > O_2^+ > O_2^- > O_2^{2-}$

Which among the following orbitals form $\delta$ molecular orbitals?

The paramagnetic molecule at ground state among the following is

Which of the following species has a bond order of $1.5$?

Which one of the following is paramagnetic?

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