Which of the following is arranged in order o | vedclass

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Question

(D) In aqueous solutions,the ionic radius is determined by the extent of hydration. Smaller ions have a higher charge density,leading to greater hydra

Vedclass · Accepted Answer

$K^{+}_{(aq)} < Na^{+}_{(aq)} < Li^{+}_{(aq)}$

Vedclass · Answer

(D) In aqueous solutions,the ionic radius is determined by the extent of hydration. Smaller ions have a higher charge density,leading to greater hydration and a larger hydrated radius.The order of ionic size for bare ions is $Li^{+} However,the extent of hydration follows the order $Li^{+} > Na^{+} > K^{+}$.Therefore,the hydrated ionic radius in aqueous solution follows the order $K^{+}_{(aq)} < Na^{+}_{(aq)} < Li^{+}_{(aq)}$.

Which of the following is arranged in order of increasing radius?

Similar Questions

The correct arrangement for the ions in the increasing order of their radii is

Assertion $(A)$: The ionic radii of $Na^{+}$ and $F^{-}$ are same.
Reason $(R)$: Both $Na^{+}$ and $F^{-}$ are isoelectronic species.
The correct answer is:

Which ion has the lowest radius from the following ions?

Which of the following ions has the maximum ionic radius?

Which of the following anions has the smallest radius?

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