Which of the following is coloured?

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(C) The colour of transition metal ions is due to the presence of unpaired electrons in the $d$-orbitals,which allow for $d-d$ transitions.$(A)$ $ScCl

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$MnSO_4$

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(C) The colour of transition metal ions is due to the presence of unpaired electrons in the $d$-orbitals,which allow for $d-d$ transitions.$(A)$ $ScCl_3$: $Sc^{3+}$ is $[Ar] 3d^0$,no unpaired electrons,colourless.$(B)$ $TiO_2$: $Ti^{4+}$ is $[Ar] 3d^0$,no unpaired electrons,colourless.$(C)$ $MnSO_4$: $Mn^{2+}$ is $[Ar] 3d^5$,has $5$ unpaired electrons,coloured.$(D)$ $ZnSO_4$: $Zn^{2+}$ is $[Ar] 3d^{10}$,no unpaired electrons,colourless.Therefore,$MnSO_4$ is coloured.

List-$I$ (Property)	List-$II$ (Metal)
$(A)$ Element that can show $+8$ oxidation state	$(1)$ $Mn$
$(B)$ $3d$ series element that can show up to $+7$ oxidation state	$(2)$ $Cr$
$(C)$ $3d$ series element with maximum melting point	$(3)$ $Os$
	$(4)$ $Fe$

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