Which of the following is the correct order of $I.E.$ (Ionization Energy)?

$X$,$Y$,and $Z$ are elements of the same period and belong to the $p$-block. $Y$ has a positive value of $\Delta_{eg}H$ (electron gain enthalpy),and $Z$ has the highest $2^{nd}$ ionization energy $(I.E.)$ among them. What is the correct order of their atomic numbers?
$(a)$ $X < Y < Z$
$(b)$ $X < Z < Y$
$(c)$ $Y < Z < X$
$(d)$ $Z < Y < X$

Compare the ionization enthalpy and electron gain enthalpy values of the elements given below:

Element Description	Element	$\Delta_{i}H_1$	$\Delta_{i}H_2$	$\Delta_{eg}H$
$(i)$ Most reactive non-metal	$(A)$	$419$	$3051$	$-48$
$(ii)$ Most reactive metal	$(B)$	$1681$	$3374$	$-328$
$(iii)$ Least reactive element	$(C)$	$738$	$1451$	$-40$
$(iv)$ Metal forming dihalide	$(D)$	$2372$	$5251$	$+48$

The set of elements that differ in mutual relationship from those of the other sets is:

Which of the following arrangements does not represent the property indicated against it?

Given below are two statements:
Statement-$I$: $C < O < N < F$ is the correct order in terms of first ionization enthalpy values.
Statement-$II$: $S > Se > Te > Po > O$ is the correct order in terms of the magnitude of electron gain enthalpy values.
In the light of the above statements, choose the correct answer from the options given below: