Which of the following is the correct order o | vedclass

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(B) The acidity of carboxylic acids depends on the stability of the carboxylate ion formed after the loss of a proton. Electron-withdrawing groups ($-

Vedclass · Accepted Answer

$ClCH_2COOH > HCOOH > CH_3COOH > C_2H_5COOH$

Vedclass · Answer

(B) The acidity of carboxylic acids depends on the stability of the carboxylate ion formed after the loss of a proton. Electron-withdrawing groups ($-I$ effect) like $-Cl$ increase acidity by stabilizing the negative charge on the carboxylate ion. Electron-donating groups ($+I$ effect) like alkyl groups decrease acidity by destabilizing the negative charge. The $+I$ effect strength follows the order: $-C_2H_5 > -CH_3 > -H$. Comparing the given acids: $1$. $ClCH_2COOH$ has a $-Cl$ group ($-I$ effect),making it the most acidic. $2$. $HCOOH$ has no alkyl group. $3$. $CH_3COOH$ has a $-CH_3$ group ($+I$ effect). $4$. $C_2H_5COOH$ has a $-C_2H_5$ group (stronger $+I$ effect than $-CH_3$),making it the least acidic. Thus,the correct order is $ClCH_2COOH > HCOOH > CH_3COOH > C_2H_5COOH$.

Which of the following is the correct order of acidity?

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