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(B) $BF_3$ acts as a Lewis acid because it is electron-deficient,and $NH_3$ acts as a Lewis base because it has a lone pair of electrons on the nitrog

Vedclass · Accepted Answer

$(i)$ is correct and $(ii)$ is incorrect

Vedclass · Answer

(B) $BF_3$ acts as a Lewis acid because it is electron-deficient,and $NH_3$ acts as a Lewis base because it has a lone pair of electrons on the nitrogen atom. In a coordinate covalent bond (dative bond),the electron pair is donated from the Lewis base to the Lewis acid. Therefore,the arrow should point from the donor $(NH_3)$ to the acceptor $(BF_3)$,which is represented in reaction $(i)$ as $F_3B \leftarrow :NH_3$. Thus,$(i)$ is correct and $(ii)$ is incorrect.

Which of the following is the correct representation of the reaction when $BF_3$ reacts with ammonia?
$(i)$ $F_3B + :NH_3 \rightarrow [F_3B \leftarrow :NH_3]$
(ii) $F_3B + :NH_3$ $\rightarrow [F_3B$ $\rightarrow :NH_3]$

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Which of the following is the correct representation of the reaction when $BF_3$ reacts with ammonia? $(i)$ $F_3B + :NH_3 \rightarrow [F_3B \leftarrow :NH_3]$ (ii) $F_3B + :NH_3$ $\rightarrow [F_3B$ $\rightarrow :NH_3]$