Which of the following is the correct structu | vedclass

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(A) $L$-glucose is the enantiomer of $D$-glucose.In $L$-glucose,the $-OH$ group on the highest numbered chiral carbon $(C-5)$ is on the left side in t

Vedclass · Accepted Answer

$CHO-C(OH)H-C(H)OH-C(OH)H-C(OH)H-CH_2OH$

Vedclass · Answer

(A) $L$-glucose is the enantiomer of $D$-glucose.In $L$-glucose,the $-OH$ group on the highest numbered chiral carbon $(C-5)$ is on the left side in the Fischer projection.All other chiral centers $(C-2, C-3, C-4)$ are also inverted relative to $D$-glucose.In $L$-glucose,the $-OH$ groups on $C-2, C-4,$ and $C-5$ are on the left,while the $-OH$ group on $C-3$ is on the right.Therefore,the correct structure is $CHO-C(OH)H-C(H)OH-C(OH)H-C(OH)H-CH_2OH$.

Which of the following is the correct structure of $L$-glucose?

Similar Questions

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