Which of the following metal carbonyl complex | vedclass

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Question

(C) $1$. $[Cr(CO)_6]$: $Cr$ is in $0$ oxidation state $(3d^5 4s^1)$. $CO$ is a strong field ligand,causing pairing. It is diamagnetic and octahedral $

Vedclass · Accepted Answer

$[Co(CO)_4]^- - 	ext{Diamagnetic} - 	ext{Tetrahedral}, sp^3$

Vedclass · Answer

(C) $1$. $[Cr(CO)_6]$: $Cr$ is in $0$ oxidation state $(3d^5 4s^1)$. $CO$ is a strong field ligand,causing pairing. It is diamagnetic and octahedral $(d^2sp^3)$.$2$. $[Fe(CO)_5]$: $Fe$ is in $0$ oxidation state $(3d^6 4s^2)$. All electrons pair up. It is diamagnetic and trigonal bipyramidal $(dsp^3)$.$3$. $[Co(CO)_4]^-$: $Co$ is in $-1$ oxidation state $(3d^8 4s^2)$. With $CO$ ligands,it becomes $3d^{10}$,which is diamagnetic and tetrahedral $(sp^3)$.$4$. $[Ni(CO)_4]$: $Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. It is diamagnetic and tetrahedral $(sp^3)$.Therefore,option $C$ is correctly matched.

Hybridisation	Geometry	Complex structure
$(A) \ sp^3$	$(i) \ \text{Square planar}$	$(p) \ [Fe(CN)_6]^{3-}$
$(B) \ d^2sp^3$	$(ii) \ \text{Tetrahedral}$	$(q) \ [ZnCl_4]^{2-}$
$(C) \ dsp^2$	$(iii) \ \text{Octahedral}$	$(r) \ [Ni(NH_3)_4]^{2+}$
-	$(iv) \ \text{Linear}$	$(s) \ [Ag(CN)_2]^-$

Which of the following metal carbonyl complexes is correctly matched with its magnetic property and geometry?

Similar Questions

What is the hybridisation and shape of $Cr$ in chromyl chloride $(CrO_2Cl_2)$?

Which of the following statements are true about $[CoF_6]^{3-}$ ion?
$I$. The complex has octahedral geometry.
$II$. Coordination number of $Co$ is $3$ and oxidation state is $+6$.
$III$. The complex is $sp^3d^2$ hybridised.
$IV$. It is a high spin complex.

Pick out the correct statement with respect to $[Mn(CN)_6]^{3-}.$

Which of the following complexes has a square planar geometry and $dsp^2$ hybridization?

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