Which of the following is most basic in natur | vedclass

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(C) In the lanthanoid series,as we move from $La$ to $Lu$,the ionic radius decreases due to lanthanoid contraction. As the ionic radius decreases,the

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$Pr(OH)_3$

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(C) In the lanthanoid series,as we move from $La$ to $Lu$,the ionic radius decreases due to lanthanoid contraction. As the ionic radius decreases,the covalent character of the $M-OH$ bond increases,which leads to a decrease in the basic strength of the hydroxides. Therefore,the basic strength follows the order: $La(OH)_3 > Pr(OH)_3 > Pm(OH)_3 > Eu(OH)_3 > Lu(OH)_3$. Among the given options,$Pr(OH)_3$ has the largest ionic radius and is therefore the most basic.

Which of the following is most basic in nature?

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