Which of the following is not correct?

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(D) The reaction between sodium thiosulphate $(Na_2S_2O_3)$ and iodine $(I_2)$ is given by: $2Na_2S_2O_3 + I_2 \rightarrow Na_2S_4O_6 + 2NaI$ In this

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Sodium thiosulphate reacts with iodine to form sodium sulphate

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(D) The reaction between sodium thiosulphate $(Na_2S_2O_3)$ and iodine $(I_2)$ is given by: $2Na_2S_2O_3 + I_2 \rightarrow Na_2S_4O_6 + 2NaI$ In this reaction,sodium thiosulphate is oxidised to sodium tetrathionate $(Na_2S_4O_6)$. Therefore,option $A$ is correct. Sodium thiosulphate is highly soluble in water,so option $B$ is correct. Ozone $(O_3)$ reacts with alkenes to form ozonides,which are then cleaved to form carbonyl compounds. This reaction is used to detect the presence of unsaturation (double or triple bonds) in organic compounds,so option $C$ is correct. Option $D$ states that sodium thiosulphate reacts with iodine to form sodium sulphate,which is incorrect as it forms sodium tetrathionate. Thus,the incorrect statement is $D$.

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