Which of the following is not correct?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. Thermal stability decreases down the group as the bond dissociation energy decreases: $H_2O > H_2S > H_2Se > H_2Te > H_2Po$. This is correct.

Vedclass · Accepted Answer

Melting point : $H_2S < H_2Se < H_2Te < H_2O$

Vedclass · Answer

(D) $1$. Thermal stability decreases down the group as the bond dissociation energy decreases: $H_2O > H_2S > H_2Se > H_2Te > H_2Po$. This is correct.$2$. Reducing property increases down the group as the bond dissociation energy decreases: $H_2S $3$. Boiling point: $H_2O$ has the highest boiling point due to hydrogen bonding. For the rest,boiling point increases with increasing molecular mass: $H_2S $4$. Melting point: The trend for melting point is $H_2S < H_2Se < H_2O < H_2Te$. $H_2O$ does not have the highest melting point compared to $H_2Te$ because of the crystal structure differences. Thus,the statement in option $D$ is incorrect.

Similar Questions

When sulphur is boiled with $Na_2SO_3$ solution,the compound formed is

How is $O_3$ estimated quantitatively?

Write a note on oxides of group-$16$ elements.

The laboratory test 'tailing of mercury' is used to identify:

Which of the following is $NOT$ a property of ozone $(O_3)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module