Which of the following is not correct?

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(D) The reaction between sodium thiosulphate $(Na_2S_2O_3)$ and iodine $(I_2)$ is given by: $2Na_2S_2O_3 + I_2 \rightarrow Na_2S_4O_6 + 2NaI$ In this

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Sodium thiosulphate reacts with iodine to form sodium sulphate.

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(D) The reaction between sodium thiosulphate $(Na_2S_2O_3)$ and iodine $(I_2)$ is given by: $2Na_2S_2O_3 + I_2 \rightarrow Na_2S_4O_6 + 2NaI$ In this reaction, sodium thiosulphate is oxidised to sodium tetrathionate $(Na_2S_4O_6)$. Therefore, option $A$ is correct. Sodium thiosulphate is highly soluble in water, so option $B$ is correct. Ozone reacts with alkenes to form ozonides, which is a standard test for unsaturation, so option $C$ is correct. Option $D$ states that sodium thiosulphate reacts with iodine to form sodium sulphate, which is incorrect as it forms sodium tetrathionate.

Column $I$	Column $II$
$(A)$ $Cu + \text{dil } HNO_3$	$(p)$ $NO$
$(B)$ $Cu + \text{conc } HNO_3$	$(q)$ $NO_2$
$(C)$ $Zn + \text{dil } HNO_3$	$(r)$ $N_2O$
$(D)$ $Zn + \text{conc } HNO_3$	$(s)$ $Cu(NO_3)_2$
	$(t)$ $Zn(NO_3)_2$

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