Which of the following is not correct for D_2 | vedclass

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(D) The solubility of ionic compounds like $NaCl$ depends on the solvation energy of the ions. In $D_2O$,the $O-D$ bond is stronger than the $O-H$ bon

Vedclass · Accepted Answer

Solubility of $NaCl$ in it is more than $H_2O$

Vedclass · Answer

(D) The solubility of ionic compounds like $NaCl$ depends on the solvation energy of the ions. In $D_2O$,the $O-D$ bond is stronger than the $O-H$ bond in $H_2O$ due to the higher mass of deuterium. This leads to a lower dielectric constant and different solvation characteristics for $D_2O$ compared to $H_2O$. Consequently,the solubility of $NaCl$ is lower in $D_2O$ than in $H_2O$. Therefore,the statement that the solubility of $NaCl$ in $D_2O$ is more than in $H_2O$ is incorrect.

Which of the following is not correct for $D_2O$?

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