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(D) The dehydration of $1-$cyclohexylpropan$-1-$ol proceeds via an $E1$ mechanism involving a carbocation intermediate.$1$. Protonation of the $-OH$ g

Vedclass · Accepted Answer

$3-$cyclohexylprop$-1-$ene

Vedclass · Answer

(D) The dehydration of $1-$cyclohexylpropan$-1-$ol proceeds via an $E1$ mechanism involving a carbocation intermediate.$1$. Protonation of the $-OH$ group followed by the loss of water generates a secondary carbocation at the $C1$ position of the propyl chain.$2$. Elimination of a proton from adjacent carbons ($C2$ of the propyl chain or the $C1$ of the cyclohexyl ring) leads to the formation of alkenes.$3$. Elimination from $C2$ of the propyl chain yields $1-$cyclohexylprop$-1-$ene (major product) and $2-$cyclohexylprop$-1-$ene (minor product).$4$. Elimination from the cyclohexyl ring leads to $1-$cyclohexylidenepropane.$5$. The structure $3-$cyclohexylprop$-1-$ene is not a product of this dehydration because it would require the migration of the double bond to a position that is not accessible through the standard $E1$ elimination pathway of the formed carbocation.

Which of the following is not the product of dehydration of $1-$cyclohexylpropan$-1-$ol?

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