Which of the following is optically active?

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(B) molecule is optically active if it possesses a chiral center (a carbon atom bonded to four different groups) and lacks an internal plane of symmet

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$CH_3-CHCl-CH_2Cl$

Vedclass · Answer

(B) molecule is optically active if it possesses a chiral center (a carbon atom bonded to four different groups) and lacks an internal plane of symmetry.$A$: $CH_3-CH_2-CHCl_2$ has two identical $Cl$ atoms on the same carbon,so it is achiral.$B$: $CH_3-CHCl-CH_2Cl$ has a chiral center at the second carbon atom,which is bonded to $-H$,$-Cl$,$-CH_3$,and $-CH_2Cl$. Since all four groups are different,it is optically active.$C$: $CH_3-CCl_2-CH_3$ has two identical $CH_3$ groups and two identical $Cl$ atoms on the central carbon,so it is achiral.$D$: $Cl-CH_2-CH_2-CH_2-Cl$ has a plane of symmetry,so it is achiral.Therefore,the correct option is $(b)$.

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