Which of the following is optically active?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The correct answer is $(D)$. An optically active compound must possess at least one chiral center and lack a plane of symmetry or center of invers

Vedclass · Accepted Answer

Tartaric acid

Vedclass · Answer

(D) The correct answer is $(D)$. An optically active compound must possess at least one chiral center and lack a plane of symmetry or center of inversion. $(A)$ Ethylene glycol $(HO-CH_2-CH_2-OH)$ has no chiral carbon. $(B)$ Oxalic acid $(HOOC-COOH)$ has no chiral carbon. $(C)$ Glycerol $(HO-CH_2-CH(OH)-CH_2-OH)$ has no chiral carbon. $(D)$ Tartaric acid $(HOOC-CH(OH)-CH(OH)-COOH)$ contains two chiral carbon atoms. While the meso-form is optically inactive due to internal compensation,the $d$- and $l$-isomers are optically active. Thus,tartaric acid is the only compound listed that can exhibit optical activity.

Similar Questions

Which among the following compounds shows optical activity?

The number of optically active products obtained from the complete ozonolysis of the given compound is $:$

Which of the following compounds exhibits stereoisomerism?

Which of the following is optically active?

Which instrument is used to measure the rotation of plane-polarized light?

Vedclass Test Series

Exam Paper Generator

Online Exam Module