Which of the following is paramagnetic as wel | vedclass

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(A) To determine the bond order and magnetic property,we use Molecular Orbital Theory $(MOT)$: $1$. For $O_2^+$ ($15$ electrons): Configuration is $(\

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$O_2^+$

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(A) To determine the bond order and magnetic property,we use Molecular Orbital Theory $(MOT)$: $1$. For $O_2^+$ ($15$ electrons): Configuration is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^1$. Bond order = $\frac{10-5}{2} = 2.5$. It has one unpaired electron,so it is paramagnetic. $2$. For $B_2$ ($10$ electrons): Configuration is $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^1 (\pi 2p_y)^1$. Bond order = $\frac{6-4}{2} = 1.0$. It is paramagnetic but has an integer bond order. $3$. For $O_2$ ($16$ electrons): Bond order = $\frac{10-6}{2} = 2.0$. It is paramagnetic but has an integer bond order. $4$. For $N_2$ ($14$ electrons): Bond order = $\frac{10-4}{2} = 3.0$. It is diamagnetic. Thus,$O_2^+$ is both paramagnetic and has a fractional bond order.

Which of the following is paramagnetic as well as it has a fractional bond order?

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